0.003x^2+0.001x=7

Solution for 0.003x^2+0.001x=7 equation:

0.003x^2+0.001x=7

We move all terms to the left:

0.003x^2+0.001x-(7)=0

a = 0.003; b = 0.001; c = -7;
Δ = b2-4ac
Δ = 0.0012-4·0.003·(-7)
Δ = 0.084001
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.001)-\sqrt{0.084001}}{2*0.003}=\frac{-0.001-\sqrt{0.084001}}{0.006}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.001)+\sqrt{0.084001}}{2*0.003}=\frac{-0.001+\sqrt{0.084001}}{0.006}
$